Estimados:
Ante todo quiero saludarlos y presentarme.
Mi nombre es Nicolás, soy de Montevideo, Uruguay y soy estudiante.
Mi consulta es la siguiente:
Necesito desarrollar un "piranómetro casero", por lo que ví en la web es posible construir uno con un panel solar, tengo en mente el siguiente panel solar cuyas características describo a continuación:
Features of the Sunforce 12V 1.8A Solar Power Panel
The Sunforce 12V 1.8A Solar Power Panel has the following features, according to the manufacturer:Sunforce 50012 Solar Battery Charger Specifications
- Maintains car, SUV, Boat, ATV, and power pack Batteries
- Easy Installation
- Charges in all weather conditions (voltage varies with light level)
- Plugs into cigarette lighter for automotive use
- Alligator battery clamps included for boat, ATV, or power pack use.
- Mounts on windshield or side window with suction cups, included
- Frame and backing: ABS Plastic
- Solar panel: amorphous silicon with glass cover
- Temperature Range: -40° to 176° F
- Max Output 1.8 Watts (125 mAh)
Mi pregunta es, ¿cómo puedo deducir los W/m2 que genera éste panel en un momento dado?
- Product Name: 1.8 Watt Solar Battery Maintainer
- Product Number: 50012 (Sunforce)
- Warranty 5 Years
- Accessories Included: Male DC (cigarette lighter) Plug, Alligator Battery Clamps & Suction Cups (MotoMaster version also included 0.25 barrel plug)
- Country of Origin: China
- External Dimensions: 20" x 1.5" x 6.5"
- Weight :1.4 Lbs.
- Inner Dimensions 7.9" x 7.3" x 20.1" (exposed area of solar panel)
Desde ya muchas gracias y disculpen si este post no debe estar aquí.


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